## Precalculus (6th Edition) Blitzer

A true statement for any $(x,y)|y=4x-5$ Our solution is: $(x,4x-5)$
Given: $y=4x-5$ Re-arrange as: $8x-2(y=4x-5)=10$ $8x-8x+10=0$ This gives: $10=10$ Thus, we get a true statement for any $(x,y)|y=4x-5$ Our solution is: $(x,4x-5)$