## Precalculus (6th Edition) Blitzer

sin t = $\frac{\sqrt 2}{2}$ , cos t = -$\frac{\sqrt 2}{2}$ tan t = -1, csc t = $\frac{2}{\sqrt 2}$ sec t = -$\frac{2}{\sqrt 2}$, cot t =-1
(-$\frac{\sqrt 2}{2}$ , $\frac{\sqrt 2}{2}$) sin t corresponds to y value So sin t = $\frac{\sqrt 2}{2}$ cos t corresponds to x value cos t = -$\frac{\sqrt 2}{2}$ tan t is computed by $\frac{y}{x}$ So tan t = $\frac{\frac{\sqrt 2}{2}}{\frac{-\sqrt 2}{2}}$ = -1 csc t = $\frac{1}{sin t}$ So, csc t = $\frac{2}{\sqrt 2}$ sec t = $\frac{1}{cos t}$ so sec t = -$\frac{2}{\sqrt 2}$ cot t = $\frac{1}{tan t}$ so cot t =-1