Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 4 - Section 4.2 - Trigonometric Functions: The Unit Circle - Exercise Set - Page 547: 2


sin t = -$\frac{12}{13}$ , cos t = -$\frac{5}{13}$ tan t = $\frac{12}{5}$, csc t = -$\frac{13}{12}$ sec t = -$\frac{13}{5}$ , cot t = $\frac{5}{12}$

Work Step by Step

(-$\frac{5}{13}$ , -$\frac{12}{13}$) sin t corresponds to y value So sin t = -$\frac{12}{13}$ cos t corresponds to x value cos t = -$\frac{5}{13}$ tan t is computed by $\frac{y}{x}$ So tan t = $\frac{\frac{-12}{13}}{\frac{-5}{13}}$ = $\frac{12}{5}$ csc t = $\frac{1}{sin t}$ So, csc t = -$\frac{13}{12}$ sec t = $\frac{1}{cos t}$ so sec t = -$\frac{13}{5}$ cot t = $\frac{1}{tan t}$ so cot t = $\frac{5}{12}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.