## Precalculus (6th Edition) Blitzer

Published by Pearson

# Chapter 4 - Section 4.2 - Trigonometric Functions: The Unit Circle - Exercise Set - Page 547: 12

#### Answer

-$\frac{2\sqrt 3}{3}$

#### Work Step by Step

(-$\frac{1}{2}$ , -$\frac{\sqrt 3}{2}$) csc $\frac{4\pi}{3}$ is computed by $\frac{1}{y}$ So csc $\frac{4\pi}{3}$ = $\frac{1}{-\frac{\sqrt 3}{2}}$ = -$\frac{2\sqrt 3}{3}$

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