## Precalculus (6th Edition) Blitzer

Published by Pearson

# Chapter 4 - Section 4.2 - Trigonometric Functions: The Unit Circle - Exercise Set: 14

2

#### Work Step by Step

($\frac{1}{2}$ , -$\frac{\sqrt 3}{2}$) sec $\frac{5\pi}{3}$ is computed by $\frac{1}{x}$. So sec $\frac{5\pi}{3}$ = $\frac{1}{\frac{1}{2}}$ = 2.

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