Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 4 - Section 4.2 - Trigonometric Functions: The Unit Circle - Exercise Set: 1

Answer

sin t = $\frac{8}{17}$ , cos t = -$\frac{15}{17}$ tan t = -$\frac{8}{15}$ , csc t = $\frac{17}{8}$ sec t = -$\frac{17}{15}$ , cot t = -$\frac{15}{8}$

Work Step by Step

(-$\frac{15}{17}$ , $\frac{8}{17}$) sin t corresponds to y value So sin t = $\frac{8}{17}$ cos t corresponds to x value cos t = -$\frac{15}{17}$ tan t is computed by $\frac{y}{x}$ So tan t = -$\frac{8}{15}$ csc t = $\frac{1}{sin t}$ So, csc t = $\frac{17}{8}$ sec t = $\frac{1}{cos t}$ so sec t = -$\frac{17}{15}$ cot t = $\frac{1}{tan t}$ so cot t = -$\frac{15}{8}$
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