Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 4 - Section 4.2 - Trigonometric Functions: The Unit Circle - Exercise Set - Page 547: 7

Answer

-$\frac{\sqrt 3}{2}$

Work Step by Step

(-$\frac{\sqrt 3}{2}$ , $\frac{1}{2}$) cos$\frac{5\pi}{6}$ corresponds to x value. So cos$\frac{5\pi}{6}$ = -$\frac{\sqrt 3}{2}$.
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