Answer
Solution set = $\{ e^{3}, e^{-3} \}$
Work Step by Step
$2|\ln x|-6=0$
$2|\ln x|=6$
$|\ln x|=3\qquad $ ...$|\ln x|=\left\{\begin{array}{ll}
x, & \ln x\geq 0\\
-x, & \ln x\lt 0
\end{array}\right.$
$\left[\begin{array}{lll}
\ln x=3 & or & \ln x=-3\\
x=e^{3} & & x=e^{-3}
\end{array}\right]$
Solution set = $\{ e^{3}, e^{-3} \}$
