Answer
$x\approx 20.67$
Work Step by Step
RECALL:
$\log_b{x}=y \longrightarrow b^y=x$
Write the equation in exponential form using the rule above to obtain:
$4^{3}=3x+2
\\64=3x+2$
Solve for $x$ to obtain:
$\begin{array}{ccc}
&64-2 &= &3x+2-2
\\&62&=&3x
\\&\frac{62}{3} &= &x
\\&x &\approx &20.67\end{array}$
