## Precalculus (6th Edition) Blitzer

$x=7.75$
RECALL: $\log_b{x}=y \longrightarrow b^y=x$ Write the equation in exponential form using the rule above to obtain: $2^{5}=4x+1 \\32=4x+1$ Solve for $x$ to obtain: $\begin{array}{ccc} &32-1&= &4x+1-1 \\&31&=&4x \\&\frac{31}{4} &= &x \\&x &=&7.75\end{array}$