## Precalculus (6th Edition) Blitzer

Solution set = $\displaystyle \{ \frac{1}{2} \}$
$5^{2x}\cdot 5^{4x}=125$ LHS: $a^{n}\cdot a^{m}=a^{n+m}$ RHS: $125=5^{3}$ $5^{2x+4x}=5^{3}$ $5^{6x}=5^{3}\qquad$ ... exponential functions are one to one. $6x=3$ $x=\displaystyle \frac{1}{2}$ Solution set = $\displaystyle \{ \frac{1}{2} \}$