Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 3 - Section 3.4 - Exponential and Logarithmic Equations - Exercise Set - Page 489: 93

Answer

Solution set = $\displaystyle \{ \frac{1}{2} \}$

Work Step by Step

$5^{2x}\cdot 5^{4x}=125$ LHS: $ a^{n}\cdot a^{m}=a^{n+m}$ RHS: $125=5^{3}$ $5^{2x+4x}=5^{3}$ $ 5^{6x}=5^{3}\qquad $ ... exponential functions are one to one. $6x=3$ $ x=\displaystyle \frac{1}{2}$ Solution set = $\displaystyle \{ \frac{1}{2} \}$
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