Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 3 - Review Exercises - Page 513: 72

Answer

$ x\approx 2.27$

Work Step by Step

$ 3^{x+4}=7^{2x-1}\qquad $ ... apply $\ln $( ) to both sides $\ln 3^{x+4}=\ln 7^{2x-1} \qquad $ ... apply $\quad \log_{b}(M^{p})=p\cdot\log_{b}\mathrm{M}$ $(x+4)\ln 3=(2x-1)\ln 7\qquad $ ... distribute $ x\ln 3+4\ln 3=2x\ln 7-\ln 7\qquad $ ... x to one side... $ x\ln 3-2x \ln 7 =-4\ln 3-\ln 7\qquad $ ... factor out x $ x(\ln 3-2\ln 7)=-4\ln 3-\ln 7\qquad $ ... divide with $(\ln 3-2\ln 7)$ $ x=\displaystyle \frac{-4\ln 3-\ln 7}{\ln 3-2\ln 7}\qquad $... use calculator and round to two decimal places $ x\approx 2.27$
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