## Precalculus (6th Edition) Blitzer

False. To become true, change it to $\displaystyle \log(x+9)-\log(x+1)=\log\frac{(x+9)}{(x+1)}$
Applying the Quotient Rule: $\displaystyle \qquad \log_{b}(\frac{M}{N})=\log_{b}\mathrm{M}-\log_{b}\mathrm{N}$, $\displaystyle \log(x+9)-\log(x+1)=\log\frac{(x+9)}{(x+1)}\neq\frac{\log(x+9)}{\log(x+1)}$ so the statement is false.