## Precalculus (6th Edition) Blitzer

$x\approx 3.85$
$10^{x}=7000$ We can't show the RHS as a power of 10, so we apply $\log($...$)$ to both sides $\log 10^{x}=\log 7000\qquad$ ... apply basic property, $\log_{b}b^{x}=x$ $x=\log 7000\qquad$ ... use a calculator and round to two decimal places $x\approx 3.85$