Precalculus (6th Edition) Blitzer

$x\approx 0.99$
$9e^{5x}=1269\qquad$...divide both sides with 9 $e^{5x}=141\qquad$ ... apply $\ln$( ) to both sides $\ln e^{5x}=\ln 141\qquad$ ... apply basic property, $\log_{b}b^{x}=x$ $5x=\ln 141\qquad$...divide both sides with 5 $x=\displaystyle \frac{\ln 141}{5}\qquad$... round to two decimal places $x\approx 0.99$