## Precalculus (6th Edition) Blitzer

False. To become true, change it to $\log_{2}x^{4}=4\log_{2}x$
Applying the Power Rule to the RHS, $\log_{b}(M^{p})=p\cdot\log_{b}\mathrm{M}$ $4\log_{2}x=\log_{2}x^{4}\quad\neq(\log_{2}x)^{2}$ so the statement is false.