#### Answer

8 dollars

#### Work Step by Step

Step 1. Identify the given quantities: $P=8000, t=3, r=0.08$
Step 2. If the interest is compounded continuously, we have
$A_1=Pe^{rt}=8000e^{0.08(3)}\approx10170$ dollars.
Step 3. If the interest is compounded monthly, we have $n=12$ and
$A_2=P(1+\frac{r}{n})^{nt}=8000(1+\frac{0.08}{12})^{12(3)}\approx10162$ dollars.
Step 4. Find the difference: $A_1-A_2=10170-10162=8$ dollars. That is the return is 8 dollars more if the interest is compounded continuously than if it is compounded monthly.