Answer
$$\sqrt{\pi }$$
Work Step by Step
We simplify as follows:
$$\log_{\pi } \pi ^{\sqrt{\pi }}=\sqrt{\pi } \log_{\pi } \pi = \sqrt{\pi } (1) = \sqrt{\pi }$$
Precalculus (6th Edition) Blitzer
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13446-914-3
ISBN 13:
978-0-13446-914-0
Chapter 3 - Mid-Chapter Check Point - Page 477: 20
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