Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 3 - Mid-Chapter Check Point - Page 477: 20


$$\sqrt{\pi }$$

Work Step by Step

We simplify as follows: $$\log_{\pi } \pi ^{\sqrt{\pi }}=\sqrt{\pi } \log_{\pi } \pi = \sqrt{\pi } (1) = \sqrt{\pi }$$
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