Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 3 - Mid-Chapter Check Point - Page 477: 11



Work Step by Step

We simplify as follows: $$\log_3\frac{1}{9}=\log_3\frac{1}{3^2}=\log_33^{-2}=-2\log_33=-2(1)=-2$$
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