Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 3 - Mid-Chapter Check Point - Page 477: 17

Answer

$$\sqrt{7}$$

Work Step by Step

We simplify as follows: $$\ln e^{\sqrt{7}}=\sqrt{7} \log_ee=\sqrt{7}(1)=\sqrt{7}$$
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