Answer
$$-\frac{1}{2}$$
Work Step by Step
We simplify as follows:
$$\log_{100}0.1=\log_{100}10^{-1}=\log_{100}(100^{\frac{1}{2}})^{-1}= \log_{100}100^{-\frac{1}{2}}=-\frac{1}{2}\log_{100}100=-\frac{1}{2}(1)=-\frac{1}{2}$$
Precalculus (6th Edition) Blitzer
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13446-914-3
ISBN 13:
978-0-13446-914-0
Chapter 3 - Mid-Chapter Check Point - Page 477: 19
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
