Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 3 - Mid-Chapter Check Point - Page 477: 25

Answer

$$\ln \left ( \frac{\sqrt{x}}{y^3(z-2)} \right )$$

Work Step by Step

We simplify as follows: $$\frac{1}{2} \ln x -3 \ln y - \ln (z-2) = \frac{1}{2} \ln x - ( 3 \ln y + \ln (z-2)) \\ = \ln x ^{\frac{1}{2}} - (\ln y^3+\ln (z-2))= \ln \sqrt{x} - \ln y^3(z-2) \\= \ln \left ( \frac{\sqrt{x}}{y^3(z-2)} \right )$$
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