Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 3 - Cumulative Review Exercises - Page 516: 1


$ x= 2, \dfrac{2}{3}$

Work Step by Step

We are given that $|3x-4|=2$ This can be written as $ 3x-4 =2; 3x-4=-2$ First consider $3 x-4 =2 \implies x=2$ Now, $3x-4 =-2 \implies x =\dfrac{2}{3}$ Our result is: $ x= 2, \dfrac{2}{3}$
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