## Precalculus (6th Edition) Blitzer

The circle is centered at $\left( 3,-2 \right)$ in the rectangular plane. And the radius of the circle is $2$. Plot the graph of the function ${{\left( x-3 \right)}^{2}}+{{\left( y+2 \right)}^{2}}=4$ as follows: Step 1: Plot the center on the coordinate plane; take $2$ units in every direction from the center $\left( h,k \right)=\left( 3,-2 \right)$. Step 2: Now, connect the dots using a smooth and round curve to get the graph. The graph of the function ${{\left( x-3 \right)}^{2}}+{{\left( y+2 \right)}^{2}}=4$ intersect the $x-\text{axis}$ at the point $\left( 3,0 \right)$.