Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 3 - Cumulative Review Exercises - Page 516: 4


$\approx 0.97$

Work Step by Step

We are given that $ e^{5x}-32=96$ Use rule: $\log_a{a^x}=x $ and simplify to obtain: $ e^{5x} =128$ Take $\ln $ of each side. $\ln e^{5x} =\ln 128$ So, $ x=\dfrac{\ln 128}{5} \approx 0.97$
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