## Precalculus (6th Edition) Blitzer

Published by Pearson

# Chapter 3 - Cumulative Review Exercises - Page 516: 4

#### Answer

$\approx 0.97$

#### Work Step by Step

We are given that $e^{5x}-32=96$ Use rule: $\log_a{a^x}=x$ and simplify to obtain: $e^{5x} =128$ Take $\ln$ of each side. $\ln e^{5x} =\ln 128$ So, $x=\dfrac{\ln 128}{5} \approx 0.97$

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