## Precalculus (6th Edition) Blitzer

Let us draw the graph of the function $f\left( x \right)={{\left( x-2 \right)}^{2}}\left( x+1 \right)$ as follows: Find the $x-\text{intercept}$ and $y\text{-intercept}$: The $x-\text{intercept}s$ are as follows: Take $y=0$ , $0={{\left( x-2 \right)}^{2}}\left( x+1 \right)$ ${{\left( x-2 \right)}^{2}}=0$ or $x+1=0$ $x=2$ And $x=-1$ So, the $x-\text{intercepts}$ are $\left( 2,0 \right)$ and $\left( -1,0 \right)$. And the $y\text{-intercept}$ is as follows: $y=0$ Use the intercepts to sketch the graph.