## Precalculus (6th Edition) Blitzer

$y=96 e^{-0.968x}$
We are given $y=96( 0.38)^x$ Re-arrange as: $y=96e^{\ln 0.38 x}$ Simplify it by applying the rule $\log e^a=a$ with $a= 0.38$ to obtain: $y=96 e^{-0.968x}$