## Precalculus (6th Edition) Blitzer

Step 1: Substitute $x=-x$. \begin{align} & f\left( x \right)=\frac{{{x}^{2}}}{{{x}^{2}}+x-6} \\ & f\left( -x \right)=\frac{{{\left( -x \right)}^{2}}}{{{\left( -x \right)}^{2}}+\left( -x \right)-6} \\ & =\frac{{{x}^{2}}}{{{x}^{2}}-x-6} \end{align} Therefore, the function $f\left( -x \right)$ is not equal to $-f\left( x \right)$ and $f\left( x \right)$. Thus, the graph of the function is not symmetric about the $y$ -axis and origin. Step 2: To calculate the x intercepts equate $f\left( x \right)=0$. $x=0$ Step 3: To calculate the y intercepts evaluate $f\left( 0 \right)$. $f\left( 0 \right)=0$ Step 4: Since the degree of the numerator is equal to the denominator, the horizontal asymptote is: $y=1$ Step 5: For the vertical asymptote, equate the denominator to 0. $x=2,-3$