Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 2 - Section 2.6 - Rational Functions and Their Graphs - Exercise Set - Page 399: 58

Answer

The graph of the function is:

Work Step by Step

Substitute $x=-x$. $\begin{align} & f\left( x \right)=\frac{3x}{x-1} \\ & f\left( -x \right)=\frac{3\left( -x \right)}{\left( -x \right)-1} \\ & =\frac{-3x}{-\left( x+1 \right)} \\ & =\frac{3x}{x+1} \end{align}$ Therefore, the function $f\left( -x \right)$ is not equal to either $f\left( x \right)$ or $-f\left( x \right)$. Hence, the graph of the function is symmetric neither about the $y$ -axis nor about the origin. To calculate the x intercepts equate $f\left( x \right)=0$. $\begin{align} & \frac{3x}{x-1}=0 \\ & x=0 \end{align}$
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