Answer
Vertical asymptote is $x=3$ and there are no holes.
Work Step by Step
If there is a rational function $f\left( x \right)=\frac{p\left( x \right)}{q\left( x \right)}$ where $p\left( x \right)$ is a numerator and $q\left( x \right)$ is a denominator then $x=a$ is a vertical asymptote of the function $f\left( x \right)$ if $x=a$ is a zero of the denominator $q\left( x \right)$.
Equate the denominator to zero.
$\begin{align}
& x-3=0 \\
& x=3
\end{align}$
Thus, $x=3$ is a vertical asymptote.
If there is a rational function $f\left( x \right)=\frac{p\left( x \right)}{q\left( x \right)}$ where $p\left( x \right)$ is the numerator and $q\left( x \right)$ is the denominator then $x=a$ is called a hole if $x-a$ is a common factor of the numerator and denominator.
There is no common factor between $x$ and $x-3$. So, there are no holes.
Hence, $x=3$ is a vertical asymptote and there are no holes.
