Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 10 - Section 10.7 - Probability - Exercise Set - Page 1118: 22


The required probability is, $\frac{1}{2}$

Work Step by Step

The sample space of equally likely outcomes is $\left\{ HH,HT,TH,TT \right\}$ and $ n\left( S \right)=4$ Assume $ E $ to be the event of getting two heads; then $ E=\left\{ HH,TT \right\}$; thus, $ n\left( E \right)=2$ Hence, the probability of two heads is: $\begin{align} & P\left( E \right)=\frac{n\left( E \right)}{n\left( S \right)} \\ & =\frac{2}{4} \\ & =\frac{1}{2} \end{align}$
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