Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 10 - Section 10.7 - Probability - Exercise Set - Page 1118: 18


The required solution of probability is, $\frac{1}{4}$

Work Step by Step

Note that with 52 cards in the deck, the total number of possible ways in which a single card is dealt is 52. Therefore, the total number of possible outcomes in the sample space is 52. That is, $ n\left( S \right)=52$ Assume, $ E $ to be the event of being dealt a diamond; then clearly $ n\left( E \right)=13$ Thus, the probability of being dealt a diamond is: $\begin{align} & P\left( E \right)=\frac{n\left( E \right)}{n\left( S \right)} \\ & =\frac{13}{52} \\ & =\frac{1}{4} \end{align}$
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