## Precalculus (6th Edition) Blitzer

The required solution of probability is, $\frac{1}{4}$
Note that with 52 cards in the deck, the total number of possible ways in which a single card is dealt is 52. Therefore, the total number of possible outcomes in the sample space is 52. That is, $n\left( S \right)=52$ Assume, $E$ to be the event of being dealt a diamond; then clearly $n\left( E \right)=13$ Thus, the probability of being dealt a diamond is: \begin{align} & P\left( E \right)=\frac{n\left( E \right)}{n\left( S \right)} \\ & =\frac{13}{52} \\ & =\frac{1}{4} \end{align}