## Precalculus (6th Edition) Blitzer

The required solution of probability is, $\frac{1}{13}$
Note that with 52 cards in the deck, the total number of possible ways in which a single card is dealt is 52. Also, the total number of possible outcomes in the sample space is 52, $n\left( S \right)=52$ Assume $E$ to be the event of being dealt a queen; then clearly $n\left( E \right)=4$ Thus, the probability of being dealt a queen is: \begin{align} & P\left( E \right)=\frac{n\left( E \right)}{n\left( S \right)} \\ & =\frac{4}{52} \\ & =\frac{1}{13} \end{align}