Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 10 - Section 10.7 - Probability - Exercise Set - Page 1118: 2


The required probability is, $\frac{37}{121}\approx 0.31$

Work Step by Step

We know that from the provided table, $ P\left( \text{never married person} \right)=\frac{\text{number of persons never married}}{\text{total number of U}\text{.S adults}}$ Thus, $\begin{align} & P\left( \text{never married person} \right)=\frac{74}{242} \\ & =\frac{37}{121} \\ & \approx 0.31 \end{align}$
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