## Precalculus (6th Edition) Blitzer

The required solution of probability is, $\frac{1}{6}$
We know that when the die is rolled, the sample space of equally likely outcomes is $S=\left\{ 1,2,3,4,5,6 \right\}$ As there are six outcomes in the sample space, therefore, $n\left( S \right)=6$ So, the event of getting a 4 can be represented by $E=\left\{ 4 \right\}$ Since there is only one outcomes in this event, therefore, $n\left( E \right)=1$ Thus, the probability of getting a 4 is given below: \begin{align} & P\left( E \right)=\frac{n\left( E \right)}{n\left( S \right)} \\ & =\frac{1}{6} \end{align}