Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 10 - Section 10.7 - Probability - Exercise Set - Page 1118: 13


The required solution of probability is, $\frac{1}{2}$

Work Step by Step

If the die is rolled, then the sample space of equally likely outcomes is $ S=\left\{ 1,2,3,4,5,6 \right\}$ As there are six outcomes in the sample space, thus, $ n\left( S \right)=6$ Also, the event of getting an odd number can be represented by $ E=\left\{ 1,3,5 \right\}$ Since there is only one outcome in this event, therefore, $ n\left( E \right)=3$ Hence, the probability of obtaining an odd number is: $\begin{align} & P\left( E \right)=\frac{n\left( E \right)}{n\left( S \right)} \\ & =\frac{3}{6} \\ & =\frac{1}{2} \end{align}$
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