Answer
The statement is false. The correct statement is, “The function $f\left( x \right)=5$ is a many-to-one function.”
Work Step by Step
Since,
$f\left( x \right)=5$
So,
$y=f\left( x \right)$
This implies: $y=5$
So, for all the inputs of x, the output y will be 5.
Therefore, for multiple inputs, there is a single output. Hence it is not a one-to-one function because for each input there is no unique output. It is a many-to-one function.
Thus, the statement is false. The correct statement is, “The function $f\left( x \right)=5$ is a many-to-one function.”
