## Precalculus (6th Edition) Blitzer

The statement is false. The correct statement is, “The function $f\left( x \right)=5$ is a many-to-one function.”
Since, $f\left( x \right)=5$ So, $y=f\left( x \right)$ This implies: $y=5$ So, for all the inputs of x, the output y will be 5. Therefore, for multiple inputs, there is a single output. Hence it is not a one-to-one function because for each input there is no unique output. It is a many-to-one function. Thus, the statement is false. The correct statement is, “The function $f\left( x \right)=5$ is a many-to-one function.”