Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 1 - Section 1.8 - Inverse Functions - Exercise Set - Page 272: 89


The statement makes sense.

Work Step by Step

Let us consider a function $f$ with $\left( x,\ y \right)$ as points on its graph where x shows the input and y shows the output. The domain of the function is the set of x and the range is the set of y. Thus the domain of the function is a range of its inverse function. Hence, domain and range of a function and its inverse are reversed.
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