Answer
a. $-5x^2+20x-7$
b. $-25x^2+40x-13$
c. $13$
d. $-33$
Work Step by Step
Given $f(x)=5x-2$ and $g(x)=-x^2+4x-1$, we have:
a. $(f\circ g)(x)=5(-x^2+4x-1)-2=-5x^2+20x-7$
b. $(g\circ f)(x)=-(5x-2)^2+4(5x-2)-1=-25x^2+20x-4+20x-8-1=-25x^2+40x-13$
c. $(f\circ g)(2)=-5(2)^2+20(2)-7=13$
d. $(g\circ f)(2)=-25(2)^2+40(2)-13=-33$
