## Precalculus (6th Edition) Blitzer

a. $x^4-6x^2+10$ b. $x^4+2x^2-2$ c. $2$ d. $22$
Given $f(x)=x^2+1$ and $g(x)=x^2-3$, we have: a. $(f\circ g)(x)=(x^2-3)^2+1=x^4-6x^2+10$ b. $(g\circ f)(x)=(x^2+1)^2-3=x^4+2x^2-2$ c. $(f\circ g)(2)=(2)^4-6(2)^2+10=2$ d. $(g\circ f)(2)=(2)^4+2(2)^2-2=22$