Answer
a. $\sqrt {x-1}$
b. $\sqrt x-1$
c. $1$
d. $\sqrt 2-1$
Work Step by Step
Given $f(x)=\sqrt x$ and $g(x)=x-1$, we have:
a. $(f\circ g)(x)=\sqrt {x-1}$
b. $(g\circ f)(x)=\sqrt x-1$
c. $(f\circ g)(2)=\sqrt {2-1}=1$
d. $(g\circ f)(2)=\sqrt 2-1$
