#### Answer

$(-2, +\infty)$

#### Work Step by Step

The denominator is not allowed to be zero as division of zero leads to an undefined expression.
This means that $x$ cannot be equal to $-2$.
The radicand (expression inside a radical) of a square root cannot be negative as its root is an imaginary number.
Thus, the value of $x$ can be any real number that is greater than or equal to $-2$.
The restrictions to the value of $x$ are:
(1) $x \ne -2$;
(2) $x \ge -2$
This means that the value of $x$ has to be greater than $-2$.
Therefore, the domain of the given function is $(-2, +\infty)$.