## Precalculus (6th Edition) Blitzer

$(-2, +\infty)$
The denominator is not allowed to be zero as division of zero leads to an undefined expression. This means that $x$ cannot be equal to $-2$. The radicand (expression inside a radical) of a square root cannot be negative as its root is an imaginary number. Thus, the value of $x$ can be any real number that is greater than or equal to $-2$. The restrictions to the value of $x$ are: (1) $x \ne -2$; (2) $x \ge -2$ This means that the value of $x$ has to be greater than $-2$. Therefore, the domain of the given function is $(-2, +\infty)$.