Answer
a. $\sqrt {x+2}$
b. $\sqrt x+2$
c. $2$
d. $\sqrt 2+2$
Work Step by Step
Given $f(x)=\sqrt x$ and $g(x)=x+2$, we have:
a. $(f\circ g)(x)=\sqrt {x+2}$
b. $(g\circ f)(x)=\sqrt x+2$
c. $(f\circ g)(2)=\sqrt {2+2}=2$
d. $(g\circ f)(2)=\sqrt 2+2$
