Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 9 - Polar Coordinates; Vectors - Chapter Review - Review Exercises - Page 635: 51



Work Step by Step

If a vector $v$ can be obtained by multiplying a vector $w$ by a constant, then $v$ and $w$ are parallel. If the dot product of two vectors is $0$ then they are orthogonal. Here $k(-2i+2j)\ne-3i+2j$, hence they are not parallel. $(-2i+2j)(-3i+2j)=(-2)(-3)+(2)(2)=6+4=10\ne0$, hence they are not orthogonal.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.