## Precalculus (10th Edition)

$3i-5j+3k$
If a vector $v$ initiates at point $P_1(x_1,y_1,z_1)$ and terminates at $P_2(x_2,y_2,z_2)$ then $v=(x_2-x_1)i+(y_2-y_1)j+(z_2-z_1)k$ Hence, $v=(4-1)i+(-2-3)j+[1-(-2)]k\\ v=3i-5j+3k$