Answer
$3i-5j+3k$
Work Step by Step
If a vector $v$ initiates at point $P_1(x_1,y_1,z_1)$ and terminates at $P_2(x_2,y_2,z_2)$ then
$v=(x_2-x_1)i+(y_2-y_1)j+(z_2-z_1)k$
Hence,
$v=(4-1)i+(-2-3)j+[1-(-2)]k\\
v=3i-5j+3k$
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