Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 9 - Polar Coordinates; Vectors - Chapter Review - Review Exercises - Page 635: 42

Answer

$0$

Work Step by Step

The magnitude of a vector $v=ai+bj+ck$ is given by the formula $||v||=\sqrt{a^2+b^2+c^2}$ Hence, $||v||=\sqrt{3^2+1^2+(-2)^2}\\ ||v||=\sqrt{9+1+4}\\ ||v||=\sqrt{14}$ $||w||=\sqrt{(-3)^2+2^2+(-1)^2}\\ ||w||=\sqrt{9+4+1}\\ ||w||=\sqrt{14}$ Therefore, $||v||-||w||=\sqrt{14}-\sqrt{14}=0$
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