Answer
$zw=6(\cos(2\pi)+i\sin{(2\pi}))$
and
$\frac{z}{w}=\frac{3}{2}(\cos({\frac{8\pi}{5})}+i\sin{\frac{8\pi}{5}})$.
Work Step by Step
We know that if $z=a(\cos{\alpha}+i\sin{\alpha})$ and $w=b(\cos{\beta}+i\sin{\beta})$, then
$zw=ab(\cos({\alpha+\beta)}+i\sin{(\alpha+\beta})$ and
$\frac{z}{w}=\frac{a}{b}(\cos({\alpha-\beta)}+i\sin{(\alpha-\beta})$.
Hence here:
$zw=(3)(2)(\cos({\frac{9\pi}{5}+\frac{\pi}{5})}+i\sin{(\frac{9\pi}{5}+\frac{\pi}{5}}))\\zw=6(\cos(2\pi)+i\sin{(2\pi}))$
and
$\frac{z}{w}=\frac{1}{1}(\cos({\frac{9\pi}{5}-\frac{\pi}{5}))}+i\sin{(\frac{9\pi}{5}-\frac{\pi}{5}}))\\\frac{z}{w}=\frac{3}{2}(\cos({\frac{8\pi}{5})}+i\sin{\frac{8\pi}{5}})$.
