Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 9 - Polar Coordinates; Vectors - Chapter Review - Review Exercises - Page 635: 35

Answer

$\frac{-2\sqrt{5}}{5}i+\frac{\sqrt{5}}{5}j.$

Work Step by Step

If $v=ai+bj$ then the unit vector $u$ in the direction of $v$ is $u=\frac{v}{||v||}$, where $||v||=\sqrt{a^2+b^2}.$ $||v||=\sqrt{(-2)^2+1^2}=\sqrt{5}.$ Hence $u=\frac{-2i+j}{\sqrt{5}}=\frac{\sqrt{5}(-2i+j)}{5}=\frac{-2\sqrt{5}}{5}i+\frac{\sqrt{5}}{5}j.$
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