Answer
$v=-i+3j$
$||v||=\sqrt{10}$
Work Step by Step
If a vector $v$ initiates at point $P(x_1,y_1)$ and terminates at $Q(x_2,y_2)$ then $v=\langle x_2-x_1,y_2-y_1\rangle=(x_2-x_1)i+(y_2-y_1)j.$
Hence, here
$v=(-1-0)i+(1-(-2))j\\
v=-i+3j$
The magnitude of a vector $v=ai+bj$ is:
$||v||=\sqrt{a^2+b^2}$.
Thus,
$||v||=\sqrt{(-1)^2+3^2}\\
||v||=\sqrt{1+9}\\
||v||=\sqrt{10}$