Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 9 - Polar Coordinates; Vectors - Chapter Review - Review Exercises - Page 635: 34

Answer

$\sqrt{5}+5$

Work Step by Step

The magnitude of a vector $v=ai+bj$ is: $||v||=\sqrt{a^2+b^2}$. Hence, $||v||=\sqrt{(-2)^2+1^2}\\ ||v||=\sqrt{4+1}\\ ||v||=\sqrt{5}$ $||w||=\sqrt{4^2+(-3)^2}\\ ||w||=\sqrt{16+9}\\ ||w||=\sqrt{25}\\ ||w||=5$ Thus, $||v||+||w||=\sqrt{5}+5$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.